On Ubuntu 16.04.1:
test.sh script:
#!/bin/bash IAM=$(whoami) ID=$(id -u $IAM) echo "${IAM}" echo "${ID}" Andromeda $ ls -al | grep test.sh -rwsrwxrwx 1 pkaramol pkaramol 71 Δεκ 8 07:52 test.sh As pkaramol (uid=1000)
Andromeda $ ./test.sh pkaramol 1000 As testuser (uid=1001)
Andromeda $ su testuser Password: testuser@Andromeda:/home/pkaramol/Desktop$ ./test.sh testuser 1001 Given that the suid has been set, why, in the second run, do we not see pkaramol and 1000 in the output? Isn't the script supposed to be executed with the file owner's id?
1 Answer
From man 2 execve, section NOTES:
Linux ignores the set-user-ID and set-group-ID bits on scripts. Also see:
