Rounding float number to the nearest tenth

Hi i have a number like 1.3333333333(THE RESULT OF PYTHON DIVISION) to round of to the nearest tenth

Input

1.333333333

Output

1.34 or 1.3

Here is what i tried

 def round(self,oj): try: (bd,ad) = oj.split(".") if int(ad[1]) >5: up = True else: up= False if up: if ad[0]==9: oj = str(int(bd)+1) else: oj = str(bd)+"."+str(int(ad[0])+1) else: oj =str( bd)+"."+ad[0] except IndexError: pass return float(oj) 

But i believe there is a better way to do it so please tell any suggestions you have

1 Answer

There are several ways you can round the number in python.

1) Use the round() function.

round(1.33333, 1) #return float 

Output: 1.3

2) Use the format() function.

"{0:.1f}".format(1.33333) #return string 

Output: 1.3

3) Use a format-string with the "%" operator

"%.1f" % 1.333333 #return string 

Output: 1.3