Reliably get IPV6 Address in Python

at the moment I do:

def get_inet_ip(): s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM) s.connect(('mysite.com', 80)) return s.getsockname()[0] 

This was based on: Finding local IP addresses using Python's stdlib

However, This looks a bit dubious. As far as I can tell, it opens a socket to mysite.com:80, and then returns the first address for that socket, assuming it to be an IPv4 address. This seems a bit dodgy... i dont think we can ever guaranteee that to be the case.

Thats my first question, is it safe? On an IPv6-enable server, could the IPv6 address ever be returned unexpectedly?

My second question, is how do I get the IPv6 address in a similar way. Im going to modify the function to take an optional ipv6 paramater.

2 Answers

The question is, do you just want to connect, or do you really want the address?

If you just want to connect, you can do

s = socket.create_connection(('mysite.com', 80)) 

and have the connection established.

However, if you are interested in the address, you can go one of these ways:

def get_ip_6(host, port=0): import socket # search only for the wanted v6 addresses result = socket.getaddrinfo(host, port, socket.AF_INET6) return result # or: return result[0][4][0] # just returns the first answer and only the address 

or, to be closer to another, already presented solution:

def get_ip_6(host, port=0): # search for all addresses, but take only the v6 ones alladdr = socket.getaddrinfo(host,port) ip6 = filter( lambda x: x[0] == socket.AF_INET6, # means its ip6 alladdr ) # if you want just the sockaddr # return map(lambda x:x[4],ip6) return list(ip6)[0][4][0] 

You should be using the function socket.getaddrinfo()

Example code to get IPv6

def get_ip_6(host,port=80): # discard the (family, socktype, proto, canonname) part of the tuple # and make sure the ips are unique alladdr = list( set( map( lambda x: x[4], socket.getaddrinfo(host,port) ) ) ) ip6 = filter( lambda x: ':' in x[0], # means its ip6 alladdr ) return ip6