Method that converts uint8_t to string

I have this:

uint8_t key[] = {0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31};

How can I convert it to char or something so that I can read its contents? this is a key i used to encrypt my data using AES.

Help is appreciated. Thanks

5 Answers

String converter(uint8_t *str){ return String((char *)str); } 

If I have understood correctly you need something like the following

#include <iostream> #include <string> #include <numeric> #include <iterator> #include <cstdint> int main() { std::uint8_t key[] = { 0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31 }; std::string s; s.reserve( 100 ); for ( int value : key ) s += std::to_string( value ) + ' '; std::cout << s << std::endl; } 

The program output is

0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 

You can remove blanks if you not need them.

Having the string you can process it as you like.

If the goal is to construct a string of 2-character hex values, you can use a string stream with IO manipulators like this:

std::string to_hex( uint8_t data[32] ) { std::ostringstream oss; oss << std::hex << std::setfill('0'); for( uint8_t val : data ) { oss << std::setw(2) << (unsigned int)val; } return oss.str(); } 

This requires the headers:

• <string>
• <sstream>
• <iomanip>

#include <sstream> // std::ostringstream #include <algorithm> // std::copy #include <iterator> // std::ostream_iterator #include <iostream> // std::cout int main(){ uint8_t key[] = {0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31}; std::ostringstream ss; std::copy(key, key+sizeof(key), std::ostream_iterator<int>(ss, ",")); std::cout << ss.str(); return 0; } 

0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29, 30,31,

You can use a stringstream:

 #include <sstream> void fnPrintArray (uint8_t key[], int length) { stringstream list; for (int i=0; i<length; ++i) { list << (int)key[i]; } string key_string = list.str(); cout << key_string << endl; }