I need to open an intent to view an image as follows:
Intent intent = new Intent(Intent.ACTION_VIEW); Uri uri = Uri.parse("@drawable/sample_1.jpg"); intent.setData(uri); startActivity(intent); The problem is that Uri uri = Uri.parse("@drawable/sample_1.jpg"); is incorrect.
7 Answers
The format is:
"android.resource://[package]/[res id]"
[package] is your package name
[res id] is value of the resource ID, e.g. R.drawable.sample_1
to stitch it together, use
Uri path = Uri.parse("android.resource://" + R.drawable.sample_1);
Here is a clean solution which fully leverages the android.net.Uri class via its Builder pattern, avoiding repeated composition and decomposition of the URI string, without relying on hard-coded strings or ad hoc ideas about URI syntax.
Resources resources = context.getResources(); Uri uri = new Uri.Builder() .scheme(ContentResolver.SCHEME_ANDROID_RESOURCE) .authority(resources.getResourcePackageName(resourceId)) .appendPath(resources.getResourceTypeName(resourceId)) .appendPath(resources.getResourceEntryName(resourceId)) .build(); Minimally more elegant with Kotlin:
fun Context.resourceUri(resourceId: Int): Uri = with(resources) { Uri.Builder() .scheme(ContentResolver.SCHEME_ANDROID_RESOURCE) .authority(getResourcePackageName(resourceId)) .appendPath(getResourceTypeName(resourceId)) .appendPath(getResourceEntryName(resourceId)) .build() } In Jetpack Compose:
@Composable fun rememberResourceUri(resourceId: Int): Uri { val context = LocalContext.current return remember(resourceId) { with(context.resources) { Uri.Builder() .scheme(ContentResolver.SCHEME_ANDROID_RESOURCE) .authority(getResourcePackageName(resourceId)) .appendPath(getResourceTypeName(resourceId)) .appendPath(getResourceEntryName(resourceId)) .build() } } } public static Uri resourceToUri(Context context, int resID) { return Uri.parse(ContentResolver.SCHEME_ANDROID_RESOURCE + "://" + context.getResources().getResourcePackageName(resID) + '/' + context.getResources().getResourceTypeName(resID) + '/' + context.getResources().getResourceEntryName(resID) ); } For those having error, you may be entering the wrong package name. Just use this method.
public static Uri resIdToUri(Context context, int resId) { return Uri.parse(Consts.ANDROID_RESOURCE + context.getPackageName() + Consts.FORESLASH + resId); } Where
public static final String ANDROID_RESOURCE = "android.resource://"; public static final String FORESLASH = "/"; You want the URI of the image resource, and R.drawable.goomb is an image resource. The Builder function creates the URI that you are asking for:
String resourceScheme = "res"; Uri uri = new Uri.Builder() .scheme(resourceScheme) .path(String.valueOf(intResourceId)) .build(); Based on the answers above I want to share a kotlin example on how to get a valid Uri for any resource in your project. I think it's the best solution because you don't have to type any strings in your code and risk typing it wrongly.
val resourceId = R.raw.scannerbeep // r.mipmap.yourmipmap; R.drawable.yourdrawable val uriBeepSound = Uri.Builder() .scheme(ContentResolver.SCHEME_ANDROID_RESOURCE) .authority(resources.getResourcePackageName(resourceId)) .appendPath(resources.getResourceTypeName(resourceId)) .appendPath(resources.getResourceEntryName(resourceId)) .build() Based on @xnagyg answer above I've made a convenience extension which hopefully will be useful for others also,
fun Resources.getRawUri(@RawRes rawRes: Int) = "%s://%s/%s/%s".format( ContentResolver.SCHEME_ANDROID_RESOURCE, this.getResourcePackageName(rawRes), this.getResourceTypeName(rawRes), this.getResourceEntryName(rawRes) ) which can be used like context.resources.getRawUri(R.raw.rawid)
