I wrote a simple code in Octave,but it keeps reporting parse error which I can't find.The code is
X = magic(3) m = size(X, 1) p = zeros(m, 1) theta = [1;2;1] hypo = 1./(1.+exp(-X*theta)); for i = 1:m if hypo(i) > 0.5 p(i) = 1; else p(i) = 0; end and Octave reports
parse error near line 12 of file F:/my document/machine learning/machine-learning-ex2/ex2/new 1.m syntax error error: source: error sourcing file 'F:/my document/machine learning/machine-learning-ex2/ex2/new 1.m' error: parse error But,there is nothing in line 12.The last line is 11.I don't know where is wrong.
2 Answers
You're missing an end to terminate the if statement. The correct code should be like this:
X = magic(3) m = size(X, 1) p = zeros(m, 1) theta = [1;2;1] hypo = 1./(1.+exp(-X*theta)); for i = 1:m if hypo(i) > 0.5 p(i) = 1; else p(i) = 0; end % <-- you forgot this! end The if statement end with endif in octave (see: ), and also the for statement with endfor (see: )
So the correct code would be:
X = magic(3) m = size(X, 1) p = zeros(m, 1) theta = [1;2;1] hypo = 1./(1.+exp(-X*theta)); for i = 1:m if hypo(i) > 0.5 p(i) = 1; else p(i) = 0; endif endfor 
