Google has not been helpful for me, since searching for "console.debug" just brings up a bunch of pages that have the words "console" and "debug" on them.
I'm wondering what the difference is between console.log() and console.debug(). Is there some way to use a bunch of console.debug() statements and then just flip a switch to easily shut off all debug statements from being sent to the console (like after launching a site)?
6 Answers
Technically console.log console.debug and console.info are identical However the way they display the data is little different. console.debug is not visible by default in the browser's JS console. It can be enabled by using the console's filter options.
console.log Black color text with no icon
console.info Blue color text with icon
console.debug Pure black color text
console.warn Yellow color text with icon
console.error Red Color text with icon
var playerOne = 120; var playerTwo = 130; var playerThree = 140; var playerFour = 150; var playerFive = 160; console.log("Console.log" + " " + playerOne); console.debug("Console.debug" + " " +playerTwo); console.warn("Console.warn" + " " + playerThree); console.info("Console.info" + " " + playerFour); console.error("Console.error" + " " + playerFive);4For at least IE, Firefox and Chrome consoles, .debug() is just an alias for .log() added for improved compatibility
5They are almost identical - the only difference is that debug messages are hidden by default in recent versions of Chrome (you have to set the log level to Verbose in the Devtools topbar while in console to see debug messages; log messages are visible by default).
console.info ,console.debug methods are identical to console.log.
console.logPrinting statementconsole.infoBlack color text with "i" icon in blue colorconsole.debugBlue Color text
Documentation:
3If you want the ability to disable logging after a product is finished you could override the console.debug() function or make another custom one.
console.debug = function() { if(!console.debugging) return; console.log.apply(this, arguments); }; console.debugging = true; console.debug('Foo', {age:41, name:'Jhon Doe'}); Foo▸ {age: 41, name: "Jhon Doe"}
console.debugging = false; console.debug('Foo', {age:26, name:'Jane Doe'}); No output
However I havent figured a way to color the outputs as well.
1From Documentation of browsers,The log,debugand also info methods are identical in implementation wise but varies in color and icon
