bash find directories

I am new to bash scripts. I'm just trying to make a script that will search through a directory and echo the names of all subdirectories.

The basis for the code is the following script (call it isitadirectory.sh):

 #!/bin/bash if test -d $1 then echo "$1" fi 

so in the command line if I type

 $bash isitadirectory.sh somefilename 

It will echo somefilename, if it is a directory.

But I want to search through all files in the parent directory.

So, I'm trying to find a way to do something like

 ls -l|isitadirectory.sh 

But of course the above command doesn't work. Can anyone explain a good script for doing this?

9 Answers

find . -mindepth 1 -maxdepth 1 -type d 

In the particular case you are looking for a 1) directory which you know the 2) name, why not trying with this:

find . -name "octave" -type d 

try to use

find $path -type d ?

for current directory

find . -type d

find ./path/to/directory -iname "test" -type d 

I found this very useful for finding directory names using -iname for case insensitive searching. Where "test" is the search term.

Following lines may give you an idea...what you are asking for

 #!/bin/bash for FILE in `ls -l` do if test -d $FILE then echo "$FILE is a subdirectory..." fi done 

You may have a look into bash 'for' loop.

Here is already much solutions, so only for fun:

 file ./**/* | grep directory | sed 's/:.*//' 

You have to use:

ls -lR | isitadirectory.sh 

(parameter -R is recursion)

Not sure.. but maybe the tree command is something you should look at.

tree -L 2 -fi 

In my case I needed the full path so I ended up using

find $(pwd) -maxdepth 1 -type d -not -path '*/\.*' | sort 

I have a lot of repos that I need to pull with one bash script. Here is the script:

#!/bin/bash cd /path/where/to/look/for/dirs # Iterate over files ending with .pub echo -e "Pulling all repos" FILES=`find $(pwd) -maxdepth 1 -type d -not -path '*/\.*' | sort` for f in $FILES do echo -e "pulling from repo $f..." cd $f git pull done