What is the correct way of using C++11's range-based for?
What syntax should be used? for (auto elem : container), or for (auto& elem : container) or for (const auto& elem : container)? Or some other?
4 Answers
TL;DR: Consider the following guidelines:
For observing the elements, use the following syntax:
for (const auto& elem : container) // capture by const referenceIf the objects are cheap to copy (like
ints,doubles, etc.), it's possible to use a slightly simplified form:for (auto elem : container) // capture by value
For modifying the elements in place, use:
for (auto& elem : container) // capture by (non-const) referenceIf the container uses "proxy iterators" (like
std::vector<bool>), use:for (auto&& elem : container) // capture by &&
Of course, if there is a need to make a local copy of the element inside the loop body, capturing by value (for (auto elem : container)) is a good choice.
Detailed Discussion
Let's start differentiating between observing the elements in the container vs. modifying them in place.
Observing the elements
Let's consider a simple example:
vector<int> v = {1, 3, 5, 7, 9}; for (auto x : v) cout << x << ' '; The above code prints the elements (ints) in the vector:
1 3 5 7 9
Now consider another case, in which the vector elements are not just simple integers, but instances of a more complex class, with custom copy constructor, etc.
// A sample test class, with custom copy semantics. class X { public: X() : m_data(0) {} X(int data) : m_data(data) {} ~X() {} X(const X& other) : m_data(other.m_data) { cout << "X copy ctor.\n"; } X& operator=(const X& other) { m_data = other.m_data; cout << "X copy assign.\n"; return *this; } int Get() const { return m_data; } private: int m_data; }; ostream& operator<<(ostream& os, const X& x) { os << x.Get(); return os; } If we use the above for (auto x : v) {...} syntax with this new class:
vector<X> v = {1, 3, 5, 7, 9}; cout << "\nElements:\n"; for (auto x : v) { cout << x << ' '; } the output is something like:
[... copy constructor calls for vector<X> initialization ...] Elements: X copy ctor. 1 X copy ctor. 3 X copy ctor. 5 X copy ctor. 7 X copy ctor. 9
As it can be read from the output, copy constructor calls are made during range-based for loop iterations.
This is because we are capturing the elements from the container by value (the auto x part in for (auto x : v)).
This is inefficient code, e.g., if these elements are instances of std::string, heap memory allocations can be done, with expensive trips to the memory manager, etc. This is useless if we just want to observe the elements in a container.
So, a better syntax is available: capture by const reference, i.e. const auto&:
vector<X> v = {1, 3, 5, 7, 9}; cout << "\nElements:\n"; for (const auto& x : v) { cout << x << ' '; } Now the output is:
[... copy constructor calls for vector<X> initialization ...] Elements: 1 3 5 7 9
Without any spurious (and potentially expensive) copy constructor call.
So, when observing elements in a container (i.e., for read-only access), the following syntax is fine for simple cheap-to-copy types, like int, double, etc.:
for (auto elem : container) Else, capturing by const reference is better in the general case, to avoid useless (and potentially expensive) copy constructor calls:
for (const auto& elem : container) Modifying the elements in the container
If we want to modify the elements in a container using range-based for, the above for (auto elem : container) and for (const auto& elem : container) syntaxes are wrong.
In fact, in the former case, elem stores a copy of the original element, so modifications done to it are just lost and not stored persistently in the container, e.g.:
vector<int> v = {1, 3, 5, 7, 9}; for (auto x : v) // <-- capture by value (copy) x *= 10; // <-- a local temporary copy ("x") is modified, // *not* the original vector element. for (auto x : v) cout << x << ' '; The output is just the initial sequence:
1 3 5 7 9
Instead, an attempt of using for (const auto& x : v) just fails to compile.
g++ outputs an error message something like this:
TestRangeFor.cpp:138:11: error: assignment of read-only reference 'x' x *= 10; ^
The correct approach in this case is capturing by non-const reference:
vector<int> v = {1, 3, 5, 7, 9}; for (auto& x : v) x *= 10; for (auto x : v) cout << x << ' '; The output is (as expected):
10 30 50 70 90
This for (auto& elem : container) syntax works also for more complex types, e.g. considering a vector<string>:
vector<string> v = {"Bob", "Jeff", "Connie"}; // Modify elements in place: use "auto &" for (auto& x : v) x = "Hi " + x + "!"; // Output elements (*observing* --> use "const auto&") for (const auto& x : v) cout << x << ' '; the output is:
Hi Bob! Hi Jeff! Hi Connie!
The special case of proxy iterators
Suppose we have a vector<bool>, and we want to invert the logical boolean state of its elements, using the above syntax:
vector<bool> v = {true, false, false, true}; for (auto& x : v) x = !x; The above code fails to compile.
g++ outputs an error message similar to this:
TestRangeFor.cpp:168:20: error: invalid initialization of non-const reference of type 'std::_Bit_reference&' from an rvalue of type 'std::_Bit_iterator::referen ce {aka std::_Bit_reference}' for (auto& x : v) ^
The problem is that std::vector template is specialized for bool, with an implementation that packs the bools to optimize space (each boolean value is stored in one bit, eight "boolean" bits in a byte).
Because of that (since it's not possible to return a reference to a single bit), vector<bool> uses a so-called "proxy iterator" pattern. A "proxy iterator" is an iterator that, when dereferenced, does not yield an ordinary bool &, but instead returns (by value) a temporary object, which is a proxy class convertible to bool. (See also this question and related answers here on StackOverflow.)
To modify in place the elements of vector<bool>, a new kind of syntax (using auto&&) must be used:
for (auto&& x : v) x = !x; The following code works fine:
vector<bool> v = {true, false, false, true}; // Invert boolean status for (auto&& x : v) // <-- note use of "auto&&" for proxy iterators x = !x; // Print new element values cout << boolalpha; for (const auto& x : v) cout << x << ' '; and outputs:
false true true false
Note that the for (auto&& elem : container) syntax also works in the other cases of ordinary (non-proxy) iterators (e.g. for a vector<int> or a vector<string>).
(As a side note, the aforementioned "observing" syntax of for (const auto& elem : container) works fine also for the proxy iterator case.)
Summary
The above discussion can be summarized in the following guidelines:
For observing the elements, use the following syntax:
for (const auto& elem : container) // capture by const referenceIf the objects are cheap to copy (like
ints,doubles, etc.), it's possible to use a slightly simplified form:for (auto elem : container) // capture by value
For modifying the elements in place, use:
for (auto& elem : container) // capture by (non-const) referenceIf the container uses "proxy iterators" (like
std::vector<bool>), use:for (auto&& elem : container) // capture by &&
Of course, if there is a need to make a local copy of the element inside the loop body, capturing by value (for (auto elem : container)) is a good choice.
Additional notes on generic code
In generic code, since we can't make assumptions about generic type T being cheap to copy, in observing mode it's safe to always use for (const auto& elem : container).
(This won't trigger potentially expensive useless copies, will work just fine also for cheap-to-copy types like int, and also for containers using proxy-iterators, like std::vector<bool>.)
Moreover, in modifying mode, if we want generic code to work also in case of proxy-iterators, the best option is for (auto&& elem : container).
(This will work just fine also for containers using ordinary non-proxy-iterators, like std::vector<int> or std::vector<string>.)
So, in generic code, the following guidelines can be provided:
For observing the elements, use:
for (const auto& elem : container)For modifying the elements in place, use:
for (auto&& elem : container)
There is no correct way to use for (auto elem : container), or for (auto& elem : container) or for (const auto& elem : container). You just express what you want.
Let me elaborate on that. Let's take a stroll.
for (auto elem : container) ... This one is syntactic sugar for:
for(auto it = container.begin(); it != container.end(); ++it) { // Observe that this is a copy by value. auto elem = *it; } You can use this one if it your container contains elements which are cheap to copy.
for (auto& elem : container) ... This one is syntactic sugar for:
for(auto it = container.begin(); it != container.end(); ++it) { // Now you're directly modifying the elements // because elem is an lvalue reference auto& elem = *it; } Use this when you want to write to the elements in the container directly, for example.
for (const auto& elem : container) ... This one is syntactic sugar for:
for(auto it = container.begin(); it != container.end(); ++it) { // You just want to read stuff, no modification const auto& elem = *it; } As the comment says, just for reading. And that's about it, everything is "correct" when used properly.
0The correct means is always
for(auto&& elem : container) This will guarantee the preservation of all semantics.
6While the initial motivation of the range-for loop might have been ease of iterating over the elements of a container, the syntax is generic enough to be useful even for objects that are not purely containers.
The syntactic requirement for the for-loop is that range_expression support begin() and end() as either functions -- either as member functions of the type that it evaluates to or as non-member functions what take an instance of the type.
As a contrived example, one can generate a range of numbers and iterate over the range using the following class.
struct Range { struct Iterator { Iterator(int v, int s) : val(v), step(s) {} int operator*() const { return val; } Iterator& operator++() { val += step; return *this; } bool operator!=(Iterator const& rhs) const { return (this->val < rhs.val); } int val; int step; }; Range(int l, int h, int s=1) : low(l), high(h), step(s) {} Iterator begin() const { return Iterator(low, step); } Iterator end() const { return Iterator(high, 1); } int low, high, step; }; With the following main function,
#include <iostream> int main() { Range r1(1, 10); for ( auto item : r1 ) { std::cout << item << " "; } std::cout << std::endl; Range r2(1, 20, 2); for ( auto item : r2 ) { std::cout << item << " "; } std::cout << std::endl; Range r3(1, 20, 3); for ( auto item : r3 ) { std::cout << item << " "; } std::cout << std::endl; } one would get the following output.
1 2 3 4 5 6 7 8 9 1 3 5 7 9 11 13 15 17 19 1 4 7 10 13 16 19