int qempty() { return (f == r ? 1 : 0); } In the above snippet, what does "?" mean? What can we replace it with?
48 Answers
This is commonly referred to as the conditional operator, and when used like this:
condition ? result_if_true : result_if_false ... if the condition evaluates to true, the expression evaluates to result_if_true, otherwise it evaluates to result_if_false.
It is syntactic sugar, and in this case, it can be replaced with
int qempty() { if(f == r) { return 1; } else { return 0; } } Note: Some people refer to ?: it as "the ternary operator", because it is the only ternary operator (i.e. operator that takes three arguments) in the language they are using.
This is a ternary operator, it's basically an inline if statement
x ? y : z works like
if(x) y else z except, instead of statements you have expressions; so you can use it in the middle of a more complex statement.
It's useful for writing succinct code, but can be overused to create hard to maintain code.
2Just a note, if you ever see this:
a = x ? : y; It's a GNU extension to the standard (see ).
It is the same as
a = x ? x : y; 1You can just rewrite it as:
int qempty(){ return(f==r);} Which does the same thing as said in the other answers.
1It is called the conditional operator.
You can replace it with:
int qempty(){ if (f == r) return 1; else return 0; } It's the conditional operator.
a ? b : c
It's a shortcut for IF/THEN/ELSE.
means: if a is true, return b, else return c. In this case, if f==r, return 1, else return 0.
The question mark is the conditional operator. The code means that if f==r then 1 is returned, otherwise, return 0. The code could be rewritten as
int qempty() { if(f==r) return 1; else return 0; } which is probably not the cleanest way to do it, but hopefully helps your understanding.
It read as:
If f == r then return 1 else return 0