I can't figure out how to rotate the text on the X Axis. Its a time stamp, so as the number of samples increase, they get closer and closer until they overlap. I'd like to rotate the text 90 degrees so as the samples get closer together, they aren't overlapping.
Below is what I have, it works fine with the exception that I can't figure out how to rotate the X axis text.
import sys import matplotlib matplotlib.use('Agg') import matplotlib.pyplot as plt import datetime font = {'family' : 'normal', 'weight' : 'bold', 'size' : 8} matplotlib.rc('font', **font) values = open('stats.csv', 'r').readlines() time = [datetime.datetime.fromtimestamp(float(i.split(',')[0].strip())) for i in values[1:]] delay = [float(i.split(',')[1].strip()) for i in values[1:]] plt.plot(time, delay) plt.grid(b='on') plt.savefig('test.png') 113 Answers
This works for me:
plt.xticks(rotation=90) 10Many "correct" answers here but I'll add one more since I think some details are left out of several. The OP asked for 90 degree rotation but I'll change to 45 degrees because when you use an angle that isn't zero or 90, you should change the horizontal alignment as well; otherwise your labels will be off-center and a bit misleading (and I'm guessing many people who come here want to rotate axes to something other than 90).
Easiest / Least Code
Option 1
plt.xticks(rotation=45, ha='right') As mentioned previously, that may not be desirable if you'd rather take the Object Oriented approach.
Option 2
Another fast way (it's intended for date objects but seems to work on any label; doubt this is recommended though):
fig.autofmt_xdate(rotation=45) fig you would usually get from:
fig = plt.gcf()fig = plt.figure()fig, ax = plt.subplots()fig = ax.figure
Object-Oriented / Dealing directly with ax
Option 3a
If you have the list of labels:
labels = ['One', 'Two', 'Three'] ax.set_xticks([1, 2, 3]) ax.set_xticklabels(labels, rotation=45, ha='right') In later versions of Matplotlib (3.5+), you can just use set_xticks alone:
ax.set_xticks([1, 2, 3], labels, rotation=45, ha='right') Option 3b
If you want to get the list of labels from the current plot:
# Unfortunately you need to draw your figure first to assign the labels, # otherwise get_xticklabels() will return empty strings. plt.draw() ax.set_xticks(ax.get_xticks()) ax.set_xticklabels(ax.get_xticklabels(), rotation=45, ha='right') As above, in later versions of Matplotlib (3.5+), you can just use set_xticks alone:
ax.set_xticks(ax.get_xticks(), ax.get_xticklabels(), rotation=45, ha='right') Option 4
Similar to above, but loop through manually instead.
for label in ax.get_xticklabels(): label.set_rotation(45) label.set_ha('right') Option 5
We still use pyplot (as plt) here but it's object-oriented because we're changing the property of a specific ax object.
plt.setp(ax.get_xticklabels(), rotation=45, ha='right') Option 6
This option is simple, but AFAIK you can't set label horizontal align this way so another option might be better if your angle is not 90.
ax.tick_params(axis='x', labelrotation=45) Edit: There's discussion of this exact "bug" but a fix hasn't been released (as of 3.4.0):
Easy way
As described here, there is an existing method in the matplotlib.pyplot figure class that automatically rotates dates appropriately for you figure.
You can call it after you plot your data (i.e.ax.plot(dates,ydata) :
fig.autofmt_xdate() If you need to format the labels further, checkout the above link.
Non-datetime objects
As per languitar's comment, the method I suggested for non-datetime xticks would not update correctly when zooming, etc. If it's not a datetime object used as your x-axis data, you should follow Tommy's answer:
for tick in ax.get_xticklabels(): tick.set_rotation(45) 2Try pyplot.setp. I think you could do something like this:
x = range(len(time)) plt.xticks(x, time) locs, labels = plt.xticks() plt.setp(labels, rotation=90) plt.plot(x, delay) 6Appart from
plt.xticks(rotation=90) this is also possible:
plt.xticks(rotation='vertical') 2I came up with a similar example. Again, the rotation keyword is.. well, it's key.
from pylab import * fig = figure() ax = fig.add_subplot(111) ax.bar( [0,1,2], [1,3,5] ) ax.set_xticks( [ 0.5, 1.5, 2.5 ] ) ax.set_xticklabels( ['tom','dick','harry'], rotation=45 ) ; 1If you want to apply rotation on the axes object, the easiest way is using tick_params. For example.
ax.tick_params(axis='x', labelrotation=90) Matplotlib documentation reference here.
This is useful when you have an array of axes as returned by plt.subplots, and it is more convenient than using set_xticks because in that case you need to also set the tick labels, and also more convenient that those that iterate over the ticks (for obvious reasons)
If using plt:
plt.xticks(rotation=90) In case of using pandas or seaborn to plot, assuming ax as axes for the plot:
ax.set_xticklabels(ax.get_xticklabels(), rotation=90) Another way of doing the above:
for tick in ax.get_xticklabels(): tick.set_rotation(45) 4My answer is inspired by cjohnson318's answer, but I didn't want to supply a hardcoded list of labels; I wanted to rotate the existing labels:
for tick in ax.get_xticklabels(): tick.set_rotation(45) 1The simplest solution is to use:
plt.xticks(rotation=XX) but also
# Tweak spacing to prevent clipping of tick-labels plt.subplots_adjust(bottom=X.XX) e.g for dates I used rotation=45 and bottom=0.20 but you can do some test for your data
import pylab as pl pl.xticks(rotation = 90) It will depend on what are you plotting.
import matplotlib.pyplot as plt x=['long_text_for_a_label_a', 'long_text_for_a_label_b', 'long_text_for_a_label_c'] y=[1,2,3] myplot = plt.plot(x,y) for item in myplot.axes.get_xticklabels(): item.set_rotation(90) For pandas and seaborn that give you an Axes object:
df = pd.DataFrame(x,y) #pandas myplot = df.plot.bar() #seaborn myplotsns =sns.barplot(y='0', x=df.index, data=df) # you can get xticklabels without .axes cause the object are already a # isntance of it for item in myplot.get_xticklabels(): item.set_rotation(90) If you need to rotate labels you may need change the font size too, you can use font_scale=1.0 to do that.
To rotate the x-axis label to 90 degrees
for tick in ax.get_xticklabels(): tick.set_rotation(45) 1