I want to remove some text from file1.txt.
I put the text in the file tmp and do:
grep -f tmp file.txt But it gives me only the difference.
The question is how to remove the difference from file.txt.
4 Answers
Doing grep -f tmp file.txt will display all lines containing the work text (assume tmp just contins the work text). If want to display all the lines that don't contain the word text you need to use the -v option to invert the match:
$ grep -v 'text' file.txt If you print all the lines in the file but just remove all occurrences of text then:
$ sed 's/text//g' If you want to remove lines from your file.txt which contains the line where text is seed then you can do something like:
sed '/text/d' file.txt or
sed -n '/text/!p' file.txt What you want to do is
grep -Fvf tmp file.txt From man grep:
-f FILE, --file=FILE Obtain patterns from FILE, one per line. The empty file contains zero patterns, and therefore matches nothing. (-f is specified by POSIX.) -F, --fixed-strings Interpret PATTERN as a list of fixed strings, separated by newlines, any of which is to be matched. (-F is specified by POSIX.) -v, --invert-match Invert the sense of matching, to select non- matching lines. (-v is specified by POSIX.) So, -f tells grep to read the list of patterns it will search for from a file. -F is needed so grep does not interpret these patterns as regular expressions. So, given a string like foo.bar, the . will be taken as a literal . and not as "match any character". Finally, the -v inverts the match so grep will print only those lines that do not match any of the patterns in tmp. For example:
$ cat pats aa bb cc $ cat file.txt This line has aa This one contains bb This one contains none of the patterns This one contains cc $ grep -Fvf pats file.txt This one contains none of the patterns What I do is:
sed '/text_to_delete/d' filename | sponge filename This will make the change to the source file.
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