How can I write the following list:
[(8, 'rfa'), (8, 'acc-raid'), (7, 'rapidbase'), (7, 'rcts'), (7, 'tve-announce'), (5, 'mysql-im'), (5, 'telnetcpcd'), (5, 'etftp'), (5, 'http-alt')] to a text file with two columns (8 rfa) and many rows, so that I have something like this:
8 rfa 8 acc-raid 7 rapidbase 7 rcts 7 tve-announce 5 mysql-im 5 telnetcpcd 7 Answers
with open('daemons.txt', 'w') as fp: fp.write('\n'.join('%s %s' % x for x in mylist)) If you want to use str.format(), replace 2nd line with:
fp.write('\n'.join('{} {}'.format(x[0],x[1]) for x in mylist)) import csv with open(<path-to-file>, "w") as the_file: csv.register_dialect("custom", delimiter=" ", skipinitialspace=True) writer = csv.writer(the_file, dialect="custom") for tup in tuples: writer.write(tup) The csv module is very powerful!
open('filename', 'w').write('\n'.join('%s %s' % x for x in mylist)) Here is the third way that I came up with:
for number, letter in myList: of.write("\n".join(["%s %s" % (number, letter)]) + "\n") simply convert the tuple to string with str()
f=open("filename.txt","w+") # in between code f.write(str(tuple)+'/n') # continue For flexibility, for example; if some items in your list contain 3 items, others contain 4 items and others contain 2 items you can do this.
mylst = [(8, 'rfa'), (8, 'acc-raid','thrd-item'), (7, 'rapidbase','thrd-item','fourth-item'),(9, 'tryrt')] # this function converts the integers to strings with a space at the end def arrtostr(item): strr='' for b in item: strr+=str(b)+' ' return strr # now write to your file with open('list.txt','w+') as doc: for line in mylst: doc.write(arrtostr(line)+'\n') doc.close() And the output in list.txt
8 rfa 8 acc-raid thrd-item 7 rapidbase thrd-item fourth-item 9 tryrt After adding f-strings in Python you can use this example:
mylst = [(8, 'rfa'), (8, 'acc-raid'), (7, 'rapidbase'), (7, 'rcts'), (7, 'tve-announce'), (5, 'mysql-im')] f = open('out.txt', mode='w+') for elem in mylst: f.write(f'{elem}\n') 
