I am trying to read a csv file into a dataframe. I know what the schema of my dataframe should be since I know my csv file. Also I am using spark csv package to read the file. I trying to specify the schema like below.
val pagecount = sqlContext.read.format("csv") .option("delimiter"," ").option("quote","") .option("schema","project: string ,article: string ,requests: integer ,bytes_served: long") .load("dbfs:/databricks-datasets/wikipedia-datasets/data-001/pagecounts/sample/pagecounts-20151124-170000") But when I check the schema of the data frame I created, it seems to have taken its own schema. Am I doing anything wrong ? how to make spark to pick up the schema I mentioned ?
> pagecount.printSchema root |-- _c0: string (nullable = true) |-- _c1: string (nullable = true) |-- _c2: string (nullable = true) |-- _c3: string (nullable = true) 13 Answers
Try the below code, you need not specify the schema. When you give inferSchema as true it should take it from your csv file.
val pagecount = sqlContext.read.format("csv") .option("delimiter"," ").option("quote","") .option("header", "true") .option("inferSchema", "true") .load("dbfs:/databricks-datasets/wikipedia-datasets/data-001/pagecounts/sample/pagecounts-20151124-170000") If you want to manually specify the schema, you can do it as below:
import org.apache.spark.sql.types._ val customSchema = StructType(Array( StructField("project", StringType, true), StructField("article", StringType, true), StructField("requests", IntegerType, true), StructField("bytes_served", DoubleType, true)) ) val pagecount = sqlContext.read.format("csv") .option("delimiter"," ").option("quote","") .option("header", "true") .schema(customSchema) .load("dbfs:/databricks-datasets/wikipedia-datasets/data-001/pagecounts/sample/pagecounts-20151124-170000") For those interested in doing this in Python here is a working version.
customSchema = StructType([ StructField("IDGC", StringType(), True), StructField("SEARCHNAME", StringType(), True), StructField("PRICE", DoubleType(), True) ]) productDF = spark.read.load('/home/ForTesting/testProduct.csv', format="csv", header="true", sep='|', schema=customSchema) testProduct.csv ID|SEARCHNAME|PRICE 6607|EFKTON75LIN|890.88 6612|EFKTON100HEN|55.66 Hope this helps.
I'm using the solution provided by Arunakiran Nulu in my analysis (see the code). Despite it is able to assign the correct types to the columns, all the values returned are null. Previously, I've tried to the option .option("inferSchema", "true") and it returns the correct values in the dataframe (although different type).
val customSchema = StructType(Array( StructField("numicu", StringType, true), StructField("fecha_solicitud", TimestampType, true), StructField("codtecnica", StringType, true), StructField("tecnica", StringType, true), StructField("finexploracion", TimestampType, true), StructField("ultimavalidacioninforme", TimestampType, true), StructField("validador", StringType, true))) val df_explo = spark.read .format("csv") .option("header", "true") .option("delimiter", "\t") .option("timestampFormat", "yyyy/MM/dd HH:mm:ss") .schema(customSchema) .load(filename) Result
root |-- numicu: string (nullable = true) |-- fecha_solicitud: timestamp (nullable = true) |-- codtecnica: string (nullable = true) |-- tecnica: string (nullable = true) |-- finexploracion: timestamp (nullable = true) |-- ultimavalidacioninforme: timestamp (nullable = true) |-- validador: string (nullable = true) and the table is:
|numicu|fecha_solicitud|codtecnica|tecnica|finexploracion|ultimavalidacioninforme|validador| +------+---------------+----------+-------+--------------+-----------------------+---------+ | null| null| null| null| null| null| null| | null| null| null| null| null| null| null| | null| null| null| null| null| null| null| | null| null| null| null| null| null| null| Thanks to the answer by @Nulu, it works for pyspark with minimal tweaking
from pyspark.sql.types import LongType, StringType, StructField, StructType, BooleanType, ArrayType, IntegerType customSchema = StructType(Array( StructField("project", StringType, true), StructField("article", StringType, true), StructField("requests", IntegerType, true), StructField("bytes_served", DoubleType, true))) pagecount = sc.read.format("com.databricks.spark.csv") .option("delimiter"," ") .option("quote","") .option("header", "false") .schema(customSchema) .load("dbfs:/databricks-datasets/wikipedia-datasets/data-001/pagecounts/sample/pagecounts-20151124-170000") The previous solutions have used the custom StructType.
With spark-sql 2.4.5 (scala version 2.12.10) it is now possible to specify the schema as a string using the schema function
import org.apache.spark.sql.SparkSession; val sparkSession = SparkSession.builder() .appName("sample-app") .master("local[2]") .getOrCreate(); val pageCount = sparkSession.read .format("csv") .option("delimiter","|") .option("quote","") .schema("project string ,article string ,requests integer ,bytes_served long") .load("dbfs:/databricks-datasets/wikipedia-datasets/data-001/pagecounts/sample/pagecounts-20151124-170000") schema definition as simple string
Just in case if some one is interested in schema definition as simple string with date and time stamp
data file creation from Terminal or shell
echo " 2019-07-02 22:11:11.000999, 01/01/2019, Suresh, abc 2019-01-02 22:11:11.000001, 01/01/2020, Aadi, xyz " > data.csv Defining the schema as String
user_schema = 'timesta TIMESTAMP,date DATE,first_name STRING , last_name STRING' reading the data
df = spark.read.csv(path='data.csv', schema = user_schema, sep=',', dateFormat='MM/dd/yyyy',timestampFormat='yyyy-MM-dd HH:mm:ss.SSSSSS') df.show(10, False) +-----------------------+----------+----------+---------+ |timesta |date |first_name|last_name| +-----------------------+----------+----------+---------+ |2019-07-02 22:11:11.999|2019-01-01| Suresh | abc | |2019-01-02 22:11:11.001|2020-01-01| Aadi | xyz | +-----------------------+----------+----------+---------+ 1Please note defining the schema explicitly instead of letting spark infer the schema also improves the spark read performance.
Here's how you can work with a custom schema, a complete demo:
$> shell code,
echo " Slingo, iOS Slingo, Android " > game.csv Scala code:
import org.apache.spark.sql.types._ val customSchema = StructType(Array( StructField("game_id", StringType, true), StructField("os_id", StringType, true) )) val csv_df = spark.read.format("csv").schema(customSchema).load("game.csv") csv_df.show csv_df.orderBy(asc("game_id"), desc("os_id")).show csv_df.createOrReplaceTempView("game_view") val sort_df = sql("select * from game_view order by game_id, os_id desc") sort_df.show if your spark version is 3.0.1, you can use following Scala scripts:
val df = spark.read.format("csv").option("delimiter",",").option("header",true).load("file:///LOCAL_CSV_FILE_PATH") but in this way, all datatypes will be set as String.
// import Library import java.io.StringReader ; import au.com.bytecode.opencsv.CSVReader //filename var train_csv = "/Path/train.csv"; //read as text file val train_rdd = sc.textFile(train_csv) //use string reader to convert in proper format var full_train_data = train_rdd.map{line => var csvReader = new CSVReader(new StringReader(line)) ; csvReader.readNext(); } //declares types type s = String // declare case class for schema case class trainSchema (Loan_ID :s ,Gender :s, Married :s, Dependents :s,Education :s,Self_Employed :s,ApplicantIncome :s,CoapplicantIncome :s, LoanAmount :s,Loan_Amount_Term :s, Credit_History :s, Property_Area :s,Loan_Status :s) //create DF RDD with custom schema var full_train_data_with_schema = full_train_data.mapPartitionsWithIndex{(idx,itr)=> if (idx==0) itr.drop(1); itr.toList.map(x=> trainSchema(x(0),x(1),x(2),x(3),x(4),x(5),x(6),x(7),x(8),x(9),x(10),x(11),x(12))).iterator }.toDF In pyspark 2.4 onwards, you can simply use header parameter to set the correct header:
data = spark.read.csv('data.csv', header=True) Similarly, if using scala you can use header parameter as well.
You can also do like this by using sparkSession and implicit
import sparkSession.implicits._ val pagecount:DataFrame = sparkSession.read .option("delimiter"," ") .option("quote","") .option("inferSchema","true") .csv("dbfs:/databricks-datasets/wikipedia-datasets/data-001/pagecounts/sample/pagecounts-20151124-170000") .toDF("project","article","requests","bytes_served") This is one of option where we can pass the column names to the dataframe while loading CSV.
import pandas names = ['sepal-length', 'sepal-width', 'petal-length', 'petal-width', 'class'] dataset = pandas.read_csv("C:/Users/NS00606317/Downloads/Iris.csv", names=names, header=0) print(dataset.head(10)) Output
sepal-length sepal-width petal-length petal-width class 1 5.1 3.5 1.4 0.2 Iris-setosa 2 4.9 3.0 1.4 0.2 Iris-setosa 3 4.7 3.2 1.3 0.2 Iris-setosa 4 4.6 3.1 1.5 0.2 Iris-setosa 5 5.0 3.6 1.4 0.2 Iris-setosa 6 5.4 3.9 1.7 0.4 Iris-setosa 7 4.6 3.4 1.4 0.3 Iris-setosa 8 5.0 3.4 1.5 0.2 Iris-setosa 9 4.4 2.9 1.4 0.2 Iris-setosa 10 4.9 3.1 1.5 0.1 Iris-setosa here my solution is:
import org.apache.spark.sql.types._ val spark = org.apache.spark.sql.SparkSession.builder. master("local[*]"). appName("Spark CSV Reader"). getOrCreate() val movie_rating_schema = StructType(Array( StructField("UserID", IntegerType, true), StructField("MovieID", IntegerType, true), StructField("Rating", DoubleType, true), StructField("Timestamp", TimestampType, true))) val df_ratings: DataFrame = spark.read.format("csv"). option("header", "true"). option("mode", "DROPMALFORMED"). option("delimiter", ","). //option("inferSchema", "true"). option("nullValue", "null"). schema(movie_rating_schema). load(args(0)) //"file:///home/hadoop/spark-workspace/data/ml-20m/ratings.csv" val movie_avg_scores = df_ratings.rdd.map(_.toString()). map(line => { // drop "[", "]" and then split the str val fileds = line.substring(1, line.length() - 1).split(",") //extract (movie id, average rating) (fileds(1).toInt, fileds(2).toDouble) }). groupByKey(). map(data => { val avg: Double = data._2.sum / data._2.size (data._1, avg) }) 
