In Python, I can create an array of evenly spaced values using
xi2 = np.arange(0, np.sqrt(6), 1e-3) How do I write this in Julia? I tried,
xi2 = range(0,sqrt(6),step=1e-3) but this returns 0.0:0.001:2.449
1 Answer
The result, 0.0:0.001:2.449 is indeed a range of evenly spaced values, and can be indexed, sliced, broadcasted on, and generally used just like any other AbstractArray. For example:
julia> xi2 = range(0,sqrt(6),step=1e-3) 0.0:0.001:2.449 julia> xi2[1] 0.0 julia> xi2[100] 0.099 julia> length(xi2) 2450 julia> isa(xi2, AbstractArray) true julia> sin.(xi2) 2450-element Vector{Float64}: 0.0 0.0009999998333333417 0.0019999986666669333 0.002999995500002025 ⋮ 0.6408405168240852 0.6400725224915994 0.6393038880866445 0.6385346143778549 If for any reason you want to turn xi2 into a full Array preemptively, you can do that with collect
julia> collect(xi2) 2450-element Vector{Float64}: 0.0 0.001 0.002 0.003 ⋮ 2.446 2.447 2.448 2.449 which will "materialize" the range, so to speak. This uses a lot more memory than the Range though, and is less often necessary than you might expect.
