I understand that in JavaScript you can write:

if (A && B) { do something }

But how do I implement an OR such as:

if (A OR B) { do something }
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11 Answers

Simply use the logical "OR" operator, that is ||.

if (A || B)
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Worth noting that || will also return true if BOTH A and B are true.

In JavaScript, if you're looking for A or B, but not both, you'll need to do something similar to:

if( (A && !B) || (B && !A) ) { ... }
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Use the || operator.

if (A || B) { do something }

|| is the or operator.

if(A || B){ do something }

here is my example:

if(userAnswer==="Yes"||"yes"||"YeS"){ console.log("Too Bad!"); }

This says that if the answer is Yes yes or YeS than the same thing will happen

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One can use regular expressions, too:

var thingToTest = "B"; if (/A|B/.test(thingToTest)) alert("Do something!")

Here's an example of regular expressions in general:

var myString = "This is my search subject" if (/my/.test(myString)) alert("Do something here!")

This will look for "my" within the variable "myString". You can substitute a string directly in place of the "myString" variable.

As an added bonus you can add the case insensitive "i" and the global "g" to the search as well.

var myString = "This is my search subject" if (/my/ig.test(myString)) alert("Do something here");
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If we're going to mention regular expressions, we might as well mention the switch statement.

var expr = 'Papayas'; switch (expr) { case 'Oranges': console.log('Oranges are $0.59 a pound.'); break; case 'Mangoes': case 'Papayas': // Mangoes or papayas console.log('Mangoes and papayas are $2.79 a pound.'); // expected output: "Mangoes and papayas are $2.79 a pound." break; default: console.log('Sorry, we are out of ' + expr + '.'); }

More then one condition statement is needed to use OR(||) operator in if conditions and notation is ||.

if(condition || condition){ some stuff }
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You can use Like

if(condition1 || condition2 || condition3 || ..........) { enter code here }
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Just use ||

if (A || B) { your action here }

Note: with string and number. It's more complicated.

Check this for deep understading:

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