I have a list:

my_list = ['element1\t0238.94', 'element2\t2.3904', 'element3\t0139847']

How can I delete the \t and everything after to get this result:

['element1', 'element2', 'element3']
0

6 Answers

Something like:

>>> l = ['element1\t0238.94', 'element2\t2.3904', 'element3\t0139847'] >>> [i.split('\t', 1)[0] for i in l] ['element1', 'element2', 'element3']
4
myList = [i.split('\t')[0] for i in myList]

Try iterating through each element of the list, then splitting it at the tab character and adding it to a new list.

for i in list: newList.append(i.split('\t')[0])
1

Do not use list as variable name. You can take a look at the following code too:

clist = ['element1\t0238.94', 'element2\t2.3904', 'element3\t0139847', 'element5'] clist = [x[:x.index('\t')] if '\t' in x else x for x in clist]

Or in-place editing:

for i,x in enumerate(clist): if '\t' in x: clist[i] = x[:x.index('\t')]

Solution with map and lambda expression:

my_list = list(map(lambda x: x.split('\t')[0], my_list))

I had to split a list for feature extraction in two parts lt,lc:

ltexts = ((df4.ix[0:,[3,7]]).values).tolist() random.shuffle(ltexts) featsets = [(act_features((lt)),lc) for lc, lt in ltexts] def act_features(atext): features = {} for word in nltk.word_tokenize(atext): features['cont({})'.format(word.lower())]=True return features