I want to convert a hex string (ex: 0xAD4) to hex number, then to add 0x200 to that number and again want to print that number in form of 0x as a string.

i tried for the first step:

str(int(str(item[1][:-2]),16)) 

but the value that is getting printed is a decimal string not a hex formatted string (in 0x format) ( i want to print the final result in form of 0x)

  • [:-2] to remove the last 00 from that number
  • item[1] is containing hex number in form of 0x
5

3 Answers

Try this:

hex_str = "0xAD4" hex_int = int(hex_str, 16) new_int = hex_int + 0x200 print hex(new_int) 

If you don't like the 0x in the beginning, replace the last line with

print hex(new_int)[2:] 
1

Use int function with second parameter 16, to convert a hex string to an integer. Finally, use hex function to convert it back to a hexadecimal number.

print hex(int("0xAD4", 16) + int("0x200", 16)) # 0xcd4 

Instead you could directly do

print hex(int("0xAD4", 16) + 0x200) # 0xcd4 
1

Use format string

intNum = 123 print "0x%x"%(intNum) 

or hex function.

intNum = 123 print hex(intNum) 
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