Related question is "Datetime To Unix timestamp", but this question is more general.

I need Unix timestamps to solve my last question. My interests are Python, Ruby and Haskell, but other approaches are welcome.

What is the easiest way to generate Unix timestamps?

3

20 Answers

In Linux or MacOS you can use:

date +%s 

where

  • +%s, seconds since 1970-01-01 00:00:00 UTC. (GNU Coreutils 8.24 Date manual)

Example output now 1454000043.

7

in Ruby:

>> Time.now.to_i => 1248933648 
2

curl icanhazepoch.com

Basically it's unix timestamps as a service (UTaaS)

1

In python add the following lines to get a time stamp:

>>> import time >>> time.time() 1335906993.995389 >>> int(time.time()) 1335906993 
$ date +%s.%N 

where (GNU Coreutils 8.24 Date manual)

  • +%s, seconds since 1970-01-01 00:00:00 UTC
  • +%N, nanoseconds (000000000..999999999) since epoch

Example output now 1454000043.704350695. I noticed that BSD manual of date did not include precise explanation about the flag +%s.

3

In Perl:

>> time => 1335552733 

The unix 'date' command is surprisingly versatile.

 date -j -f "%a %b %d %T %Z %Y" "`date`" "+%s" 

Takes the output of date, which will be in the format defined by -f, and then prints it out (-j says don't attempt to set the date) in the form +%s, seconds since epoch.

2

First of all, the Unix 'epoch' or zero-time is 1970-01-01 00:00:00Z (meaning midnight of 1st January 1970 in the Zulu or GMT or UTC time zone). A Unix time stamp is the number of seconds since that time - not accounting for leap seconds.

Generating the current time in Perl is rather easy:

perl -e 'print time, "\n"' 

Generating the time corresponding to a given date/time value is rather less easy. Logically, you use the strptime() function from POSIX. However, the Perl POSIX::strptime module (which is separate from the POSIX module) has the signature:

($sec, $min, $hour, $mday, $mon, $year, $wday, $yday) = POSIX::strptime("string", "Format"); 

The function mktime in the POSIX module has the signature:

mktime(sec, min, hour, mday, mon, year, wday = 0, yday = 0, isdst = 0) 

So, if you know the format of your data, you could write a variant on:

perl -MPOSIX -MPOSIX::strptime -e \ 'print mktime(POSIX::strptime("2009-07-30 04:30", "%Y-%m-%d %H:%M")), "\n"' 

in Haskell

import Data.Time.Clock.POSIX main :: IO () main = print . floor =<< getPOSIXTime 

in Go

import "time" t := time.Unix() 

in C

time(); // in time.h POSIX // for Windows time.h #define UNIXTIME(result) time_t localtime; time(&localtime); struct tm* utctime = gmtime(&localtime); result = mktime(utctime); 

in Swift

NSDate().timeIntervalSince1970 // or Date().timeIntervalSince1970 

In Bash 5 there's a new variable:

echo $EPOCHSECONDS 

Or if you want higher precision (in microseconds):

echo $EPOCHREALTIME 

For completeness, PHP:

php -r 'echo time();' 

In BASH:

clitime=$(php -r 'echo time();') echo $clitime 
1

In Haskell...

To get it back as a POSIXTime type:

import Data.Time.Clock.POSIX getPOSIXTime 

As an integer:

import Data.Time.Clock.POSIX round `fmap` getPOSIXTime 
public static Int32 GetTimeStamp() { try { Int32 unixTimeStamp; DateTime currentTime = DateTime.Now; DateTime zuluTime = currentTime.ToUniversalTime(); DateTime unixEpoch = new DateTime(1970, 1, 1); unixTimeStamp = (Int32)(zuluTime.Subtract(unixEpoch)).TotalSeconds; return unixTimeStamp; } catch (Exception ex) { Debug.WriteLine(ex); return 0; } } 

Let's try JavaScript:

var t = Math.floor((new Date().getTime()) / 1000); 

...or even nicer, the static approach:

var t = Math.floor(Date.now() / 1000); 

In both cases I divide by 1000 to go from seconds to millis and I use Math.floor to only represent whole seconds that have passed (vs. rounding, which might round up to a whole second that hasn't passed yet).

2

If I want to print utc date time using date command I need to using -u argument with date command.

Example

date -u 

Output

Fri Jun 14 09:00:42 UTC 2019 

nawk:

$ nawk 'BEGIN{print srand()}' 
  • Works even on old versions of Solaris and probably other UNIX systems, where '''date +%s''' isn't implemented
  • Doesn't work on Linux and other distros where the posix tools have been replaced with the GNU versions (nawk -> gawk etc.)
  • Pretty unintuitive but definitelly amusing :-)

For Unix-like environment the following will work.

# Current UNIXTIME unixtime() { datetime2unixtime "$(date -u +'%Y-%m-%d %H:%M:%S')" } # From DateTime(%Y-%m-%d %H:%M:%S)to UNIXTIME datetime2unixtime() { set -- "${1%% *}" "${1##* }" set -- "${1%%-*}" "${1#*-}" "${2%%:*}" "${2#*:}" set -- "$1" "${2%%-*}" "${2#*-}" "$3" "${4%%:*}" "${4#*:}" set -- "$1" "${2#0}" "${3#0}" "${4#0}" "${5#0}" "${6#0}" [ "$2" -lt 3 ] && set -- $(( $1-1 )) $(( $2+12 )) "$3" "$4" "$5" "$6" set -- $(( (365*$1)+($1/4)-($1/100)+($1/400) )) "$2" "$3" "$4" "$5" "$6" set -- "$1" $(( (306*($2+1)/10)-428 )) "$3" "$4" "$5" "$6" set -- $(( ($1+$2+$3-719163)*86400+$4*3600+$5*60+$6 )) echo "$1" } # From UNIXTIME to DateTime format(%Y-%m-%d %H:%M:%S) unixtime2datetime() { set -- $(( $1%86400 )) $(( $1/86400+719468 )) 146097 36524 1461 set -- "$1" "$2" $(( $2-(($2+2+3*$2/$3)/$5)+($2-$2/$3)/$4-(($2+1)/$3) )) set -- "$1" "$2" $(( $3/365 )) set -- "$@" $(( $2-( (365*$3)+($3/4)-($3/100)+($3/400) ) )) set -- "$@" $(( ($4-($4+20)/50)/30 )) set -- "$@" $(( 12*$3+$5+2 )) set -- "$1" $(( $6/12 )) $(( $6%12+1 )) $(( $4-(30*$5+3*($5+4)/5-2)+1 )) set -- "$2" "$3" "$4" $(( $1/3600 )) $(( $1%3600 )) set -- "$1" "$2" "$3" "$4" $(( $5/60 )) $(( $5%60 )) printf "%04d-%02d-%02d %02d:%02d:%02d\n" "$@" } # Examples unixtime # => Current UNIXTIME date +%s # Linux command datetime2unixtime "2020-07-01 09:03:13" # => 1593594193 date -u +%s --date "2020-07-01 09:03:13" # Linux command unixtime2datetime "1593594193" # => 2020-07-01 09:03:13 date -u --date @1593594193 +"%Y-%m-%d %H:%M:%S" # Linux command 

With NodeJS, just open a terminal and type:
node -e "console.log(new Date().getTime())" or node -e "console.log(Date.now())"

In Rust:

use std::time::{SystemTime, UNIX_EPOCH}; fn main() { let now = SystemTime::now(); println!("{}", now.duration_since(UNIX_EPOCH).unwrap().as_secs()) } 

If you need a Unix timestamp from a shell script (Bourne family: sh, ksh, bash, zsh, ...), this should work on any Unix machine as unlike the other suggestions (perl, haskell, ruby, python, GNU date), it is based on a POSIX standard command and feature.

PATH=`getconf PATH` awk 'BEGIN {srand();print srand()}' 

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