sample1 = read.csv("pirate.csv") sample1[,7] [1] >>xyz>>hello>>mate 1 [2] >>xyz>>hello>>mate 2 [3] >>xyz>>mate 3 [4] >>xyz>>mate 4 [5] >>xyz>>hello>>mate 5 [6] >>xyz>>hello>>mate 6 I have to extract and create an array which contains all the words after last >>.
How to do this?
Also, How can I extract (a) o qwerty, (b) mate1 and (c) pirate1 in different variables from the following string
p= '>>xyz- o qwerty>>hello>>mate1>>sole pirate1' Thanks
62 Answers
x <- c('>>xyz>>hello>>mate 1', '>>xyz>>hello>>mate 2', '>>xyz>>mate 3', ' >>xyz>>mate 4' ,'>>xyz>>hello>>mate 5') sub('.*>>', '', x) #[1] "mate 1" "mate 2" "mate 3" "mate 4" "mate 5" 6Assuming you already read that stuff into an R data frame, you can use stringr package as follows:
library(stringr) str_extract(df$mystring, '\\S+$') For example, if you have string like this:
s <- '>>hello1>>hola1>>ahoy mate1' You get:
str_extract(s, '\\S+$') [1] "mate1" 3