I have a school project and I have to use the AM in the Student.h as a char*.The AM have to have numbers in it. I can't understand why what I am doing is not working. Student.cpp
#include <iostream> #include <string> #include "Student.h" using namespace std; int main() { Student dlg; dlg.AM[10]={2,1,3,9,0,2,6,6}; } Student.h
#pragma once #include <string> using namespace std; class Student { public: char *AM[20]; string Name; unsigned int Semester = 1; }; 1 Answer
If you really need your student number to be a char string, then you need to convert your ints to char* before assigning them to the array.
int main() { Student dlg; int j = 0; for (auto i : {2,1,3,9,0,2,6,6}) { auto strInt { std::to_string(i) }; // create a C++ string containing a int // next copy the internal memory of the C++ string to a read-writable memory buffer // and assign a pointer to that buffer casted to a char* to the appropriate slot in the array dlg.AM[j++] = static_cast<char*> (std::memcpy (new char[16], strInt.c_str(), strInt.size())); } // test for (int i = 0; i < 8; i++) { cout << dlg.AM[i] << ' '; } } Are you sure the student number should be a char* ?
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