I Have a vb6 application using crystal report 8.5 and sql server 2005.My issue is that when I print report i get Server has not yet been opened.Here is my code in vb.:

Option Explicit Dim ctr As Integer Dim cn As New ADODB.Connection--Provider=SQLOLEDB.1;Password=password;Persist Security Info=True;User ID=user ID;Initial Catalog=database Name;Data Source=server Name Dim crApp As CRAXDRT.Application Dim crReport As CRAXDRT.Report Dim crtable As CRAXDRT.DatabaseTable Private Sub prin_Click() Dim rs As New ADODB.Recordset Set cn = New ADODB.Connection cn.ConnectionString = MDI1.txtado cn.Open Set rs = New ADODB.Recordset rs.Open "select * from temp_abs_yes", cn, adOpenKeyset, adLockOptimistic Set crApp = New CRAXDRT.Application Set crReport = crApp.OpenReport("C:\Users\user1.dom\Desktop\ANP\abs_yes.rpt") crReport.Database.Tables.Item(1).SetLogOnInfo "servername", "databasename", "user", "password" crReport.Database.Tables.Item(1).SetDataSource rs, 3 crReport.DiscardSavedData Viewer.ReportSource = crReport Viewer.ViewReport rs.close Set rs = Nothing Set crReport = Nothing Set crApp = Nothing End Sub 

2 Answers

I think doing "SetLogOnInfo" is innecesary in that case, as you are assigning the data to report

Probably is not your case, but for the help of someone else.

I got that error when I assigned the servername parameter incorrectly.

The correct parameters I used for logon (for an oracle DB):

[...]Item(1).SetLogOnInfo "[tnsnames]", "", "[db user]", "[db password]"

1

I resolved by updating dll

p2soledb.dll

in c:\Windows\Crystal I got the details from here

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