How can I convert the following timestamp into the an integer form, ideally milliseconds after 1970....
s = '2014-02-11-00_40_05' I have tried using:
out = datevec(s) However I receive an error saying 'Too many date fields in 2014-02-11-00_40_0'
Thanks
12 Answers
Try datenum with a format specifier:
>> datenum(s,'yyyy-mm-dd-hh_MM_ss') ans = 7.3564e+05 Convert to epoch:
mtime = datenum(s,'yyyy-mm-dd-hh_MM_ss'); unix_time = round(8.64e7 * (mtime - datenum('1970', 'yyyy'))) Assuming 02 in your example is month (otherwise change format string in the obvious way):
datenum('2014-02-11-00_40_05','yyyy-mm-dd-HH_MM_SS') gives you seconds after Jan-1-0000. From that it's easy to get miliseconds after 1970:
( datenum('2014-02-11-00_40_05','yyyy-mm-dd-HH_MM_SS') - ... datenum('1970-01-01-00_00_00','yyyy-mm-dd-HH_MM_SS') ) * 1000 
