I am working on an Android application. In my app I have to convert a string to JSON Object, then parse the values. I checked for a solution in Stackoverflow and found similar issue here link

The solution is like this

 `{"phonetype":"N95","cat":"WP"}` JSONObject jsonObj = new JSONObject("{\"phonetype\":\"N95\",\"cat\":\"WP\"}");

I use the same way in my code . My string is

{"ApiInfo":{"description":"userDetails","status":"success"},"userDetails":{"Name":"somename","userName":"value"},"pendingPushDetails":[]} string mystring= mystring.replace("\"", "\\\"");

And after replace I got the result as this

{\"ApiInfo\":{\"description\":\"userDetails\",\"status\":\"success\"},\"userDetails\":{\"Name\":\"Sarath Babu\",\"userName\":\"sarath.babu.sarath babu\",\"Token\":\"ZIhvXsZlKCNL6Xj9OPIOOz3FlGta9g\",\"userId\":\"118\"},\"pendingPushDetails\":[]}

when I execute JSONObject jsonObj = new JSONObject(mybizData);

I am getting the below JSON exception

org.json.JSONException: Expected literal value at character 1 of

Please help me to solve my issue.

3

9 Answers

Remove the slashes:

String json = {"phonetype":"N95","cat":"WP"}; try { JSONObject obj = new JSONObject(json); Log.d("My App", obj.toString()); } catch (Throwable t) { Log.e("My App", "Could not parse malformed JSON: \"" + json + "\""); }
10

This method works

 String json = "{\"phonetype\":\"N95\",\"cat\":\"WP\"}"; try { JSONObject obj = new JSONObject(json); Log.d("My App", obj.toString()); Log.d("phonetype value ", obj.getString("phonetype")); } catch (Throwable tx) { Log.e("My App", "Could not parse malformed JSON: \"" + json + "\""); }
2

try this:

String json = "{'phonetype':'N95','cat':'WP'}";
3

You just need the lines of code as below:

 try { String myjsonString = "{\"phonetype\":\"N95\",\"cat\":\"WP\"}"; JSONObject jsonObject = new JSONObject(myjsonString ); //displaying the JSONObject as a String Log.d("JSONObject = ", jsonObject.toString()); //getting specific key values Log.d("phonetype = ", jsonObject.getString("phonetype")); Log.d("cat = ", jsonObject.getString("cat"); }catch (Exception ex) { StringWriter stringWriter = new StringWriter(); ex.printStackTrace(new PrintWriter(stringWriter)); Log.e("exception ::: ", stringwriter.toString()); }

just try this , finally this works for me :

//delete backslashes ( \ ) : data = data.replaceAll("[\\\\]{1}[\"]{1}","\""); //delete first and last double quotation ( " ) : data = data.substring(data.indexOf("{"),data.lastIndexOf("}")+1); JSONObject json = new JSONObject(data);

To get a JSONObject or JSONArray from a String I've created this class: 

public static class JSON { public Object obj = null; public boolean isJsonArray = false; JSON(Object obj, boolean isJsonArray){ this.obj = obj; this.isJsonArray = isJsonArray; } }

Here to get the JSON:

public static JSON fromStringToJSON(String jsonString){ boolean isJsonArray = false; Object obj = null; try { JSONArray jsonArray = new JSONArray(jsonString); Log.d("JSON", jsonArray.toString()); obj = jsonArray; isJsonArray = true; } catch (Throwable t) { Log.e("JSON", "Malformed JSON: \"" + jsonString + "\""); } if (object == null) { try { JSONObject jsonObject = new JSONObject(jsonString); Log.d("JSON", jsonObject.toString()); obj = jsonObject; isJsonArray = false; } catch (Throwable t) { Log.e("JSON", "Malformed JSON: \"" + jsonString + "\""); } } return new JSON(obj, isJsonArray); }

Example:

JSON json = fromStringToJSON("{\"message\":\"ciao\"}"); if (json.obj != null) { // If the String is a JSON array if (json.isJsonArray) { JSONArray jsonArray = (JSONArray) json.obj; } // If it's a JSON object else { JSONObject jsonObject = (JSONObject) json.obj; } }
1

Using Kotlin

 val data = "{\"ApiInfo\":{\"description\":\"userDetails\",\"status\":\"success\"},\"userDetails\":{\"Name\":\"somename\",\"userName\":\"value\"},\"pendingPushDetails\":[]}\n" try { val jsonObject = JSONObject(data) val infoObj = jsonObject.getJSONObject("ApiInfo") } catch (e: Exception) { }

Here is the code, and you can decide which
(synchronized)StringBuffer or faster StringBuilder to use.

Benchmark shows StringBuilder is Faster.

public class Main { int times = 777; long t; { StringBuffer sb = new StringBuffer(); t = System.currentTimeMillis(); for (int i = times; i --> 0 ;) { sb.append(""); getJSONFromStringBuffer(String stringJSON); } System.out.println(System.currentTimeMillis() - t); } { StringBuilder sb = new StringBuilder(); t = System.currentTimeMillis(); for (int i = times; i --> 0 ;) { getJSONFromStringBUilder(String stringJSON); sb.append(""); } System.out.println(System.currentTimeMillis() - t); } private String getJSONFromStringBUilder(String stringJSONArray) throws JSONException { return new StringBuffer( new JSONArray(stringJSONArray).getJSONObject(0).getString("phonetype")) .append(" ") .append( new JSONArray(employeeID).getJSONObject(0).getString("cat")) .toString(); } private String getJSONFromStringBuffer(String stringJSONArray) throws JSONException { return new StringBuffer( new JSONArray(stringJSONArray).getJSONObject(0).getString("phonetype")) .append(" ") .append( new JSONArray(employeeID).getJSONObject(0).getString("cat")) .toString(); } }

May be below is better.

JSONObject jsonObject=null; try { jsonObject=new JSONObject(); jsonObject.put("phonetype","N95"); jsonObject.put("cat","wp"); String jsonStr=jsonObject.toString(); } catch (JSONException e) { e.printStackTrace(); }