Adding a newline into a string in C#

I have a string.

string strToProcess = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@"; 

I need to add a newline after every occurence of "@" symbol in the string.

My Output should be like this

fkdfdsfdflkdkfk@ dfsdfjk72388389@ kdkfkdfkkl@ jkdjkfjd@ jjjk@ 

13 Answers

Use Environment.NewLine whenever you want in any string. An example:

string text = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@"; text = text.Replace("@", "@" + System.Environment.NewLine); 

You can add a new line character after the @ symbol like so:

string newString = oldString.Replace("@", "@\n"); 

You can also use the NewLine property in the Environment Class (I think it is Environment).

The previous answers come close, but to meet the actual requirement that the @ symbol stay close, you'd want that to be str.Replace("@", "@" + System.Environment.NewLine). That will keep the @ symbol and add the appropriate newline character(s) for the current platform.

Then just modify the previous answers to:

Console.Write(strToProcess.Replace("@", "@" + Environment.NewLine)); 

If you don't want the newlines in the text file, then don't preserve it.

A simple string replace will do the job. Take a look at the example program below:

using System; namespace NewLineThingy { class Program { static void Main(string[] args) { string str = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@"; str = str.Replace("@", "@" + Environment.NewLine); Console.WriteLine(str); Console.ReadKey(); } } } 

as others have said new line char will give you a new line in a text file in windows. try the following:

using System; using System.IO; static class Program { static void Main() { WriteToFile ( @"C:\test.txt", "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@", "@" ); /* output in test.txt in windows = fkdfdsfdflkdkfk@ dfsdfjk72388389@ kdkfkdfkkl@ jkdjkfjd@ jjjk@ */ } public static void WriteToFile(string filename, string text, string newLineDelim) { bool equal = Environment.NewLine == "\r\n"; //Environment.NewLine == \r\n = True Console.WriteLine("Environment.NewLine == \\r\\n = {0}", equal); //replace newLineDelim with newLineDelim + a new line //trim to get rid of any new lines chars at the end of the file string filetext = text.Replace(newLineDelim, newLineDelim + Environment.NewLine).Trim(); using (StreamWriter sw = new StreamWriter(File.OpenWrite(filename))) { sw.Write(filetext); } } } 

string strToProcess = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@"; var result = strToProcess.Replace("@", "@ \r\n"); Console.WriteLine(result); 

Output

string str = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@"; str = str.Replace("@", Environment.NewLine); richTextBox1.Text = str; 

Based on your replies to everyone else, something like this is what you're looking for.

string file = @"C:\file.txt"; string strToProcess = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@"; string[] lines = strToProcess.Split(new char[] { '@' }, StringSplitOptions.RemoveEmptyEntries); using (StreamWriter writer = new StreamWriter(file)) { foreach (string line in lines) { writer.WriteLine(line + "@"); } } 

Change your string as mentioned below.

string strToProcess = "fkdfdsfdflkdkfk"+ System.Environment.NewLine +" dfsdfjk72388389"+ System.Environment.NewLine +"kdkfkdfkkl"+ System.Environment.NewLine +"jkdjkfjd"+ System.Environment.NewLine +"jjjk"+ System.Environment.NewLine; 

You could also use string[] something = text.Split('@'). Make sure you use single quotes to surround the "@" to store it as a char type. This will store the characters up to and including each "@" as individual words in the array. You can then output each (element + System.Environment.NewLine) using a for loop or write it to a text file using System.IO.File.WriteAllLines([file path + name and extension], [array name]). If the specified file doesn't exist in that location it will be automatically created.

protected void Button1_Click(object sender, EventArgs e) { string str = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@"; str = str.Replace("@", "@" + "<br/>"); Response.Write(str); } 

using System; using System.IO; using System.Text; class Test { public static void Main() { string strToProcess = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@"; strToProcess.Replace("@", Environment.NewLine); Console.WriteLine(strToProcess); } }